The solutions of x are 1 and [tex]-\frac{5}{2}[/tex]
Step-by-step explanation:
Given,quadratic equation is
[tex]2x^2+3x-5=0[/tex]
[tex]\Leftrightarrow x = \frac{-3\pm\sqrt{3^2+4.2.(-5)} }{2.2}[/tex] [ [tex]x=\frac{-b\pm \sqrt{b^2 -4ac} }{2a}[/tex] here a =2, b= 3 and c= -5]
[tex]\Leftrightarrow x = \frac{-3\pm\sqrt{49} }{2.2}[/tex]
[tex]\Leftrightarrow x = \frac{-3\pm7}{4}[/tex]
Either x =1 or, [tex]x = -\frac{5}{2}[/tex]