Respuesta :

The solutions of x are 1 and [tex]-\frac{5}{2}[/tex]

Step-by-step explanation:

Given,quadratic equation is

[tex]2x^2+3x-5=0[/tex]

[tex]\Leftrightarrow x = \frac{-3\pm\sqrt{3^2+4.2.(-5)} }{2.2}[/tex]                       [ [tex]x=\frac{-b\pm \sqrt{b^2 -4ac} }{2a}[/tex]  here a =2, b= 3 and c= -5]

[tex]\Leftrightarrow x = \frac{-3\pm\sqrt{49} }{2.2}[/tex]

[tex]\Leftrightarrow x = \frac{-3\pm7}{4}[/tex]

Either x =1  or, [tex]x = -\frac{5}{2}[/tex]

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