Question

A kinetics experiment is set up to collect the gas that is generated when a sample of chalk, consisting primarily of solid CaCO3, is added to a solution of ethanoic acid, CH3COOH. The rate of reaction between the CaCO3 and CH3COOH is determined by measuring the volume of gas generated at 25oC and 1 atm as a function of time. Which of the following experimental conditions is most likely to increase the rate of gas production?

A) Decreasing the volume of ethanoic acid solution used in the experiment
B) Decreasing the concentration of the ethanoic acid solution used in the experiment
C) Decreasing the temperature at which the experiment is performed
D) Decreasing the particle size of the CaCO3 by grinding it into a fine powder

Answer 1

Answer:

option D

Explanation:

Reaction between $CaCO_3$ and $CH_3COOH$ is as follows:

$CaCO_3+2CH_3COOH \rightarrow Ca(CH_3COO)_2+H_2O+CO_2$

For increasing the rate of gas production, rate of reaction should be increased.

$CaCO_3$ is solid, therefore, increase in surface area, will increase the rate of reaction. Grinding of particles into fine powder will increase the surface area and hence, will increase the rate of the reaction.

Therefore, option D is correct

Answer 2

The rate of reaction has been increased with the grinding of the calcium carbonate in the mixture. Thus, option D is correct.

The balanced chemical equation for the reaction has been given as:

$\rm CaCO_3\;+\;2\;CH_3COOH\;\rightarrow\;Ca(CH_3COOH)_2\;+\;H_2O\;+\;CO_2$

The rate of reaction has been given as the rate of formation of product or the disappearance of reactants.

Rate of reaction

For the increase in the rate of reaction at the specifies conditions, there has been an increase in the rate of formation of product.

The rate of product formation has been dependent on the reactants in the mixture. There has been an increase in the reacting reactant, result in the increase rate of reaction.

The reacting surface has been increased with the grinding of the calcium carbonate in the mixture. Thus, option D is correct.

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