Question

A 2 kg ball is attached to a 0.80 m string and whirled in a horizontal circle at a constant speed of 6 m/s. The work done on the ball during each revolution is ___.

Answer 1

Answer:

72 J

Explanation:

m = 2kg

r = 0.80m

v = 6m/s

W = ?

W = Force × distance

= mv²/r × r

= mv²

= 2×6²

=2×36

= 72J