The equation sin (25 degree) equals StartFraction 9 Over c EndFraction can be used to find the length of Line segment A B.

Triangle A B C is shown. Angle A C B is 90 degrees and angle B A C is 25 degrees. The length of B C is 9 inches and the length of hypotenuse B A is c.

What is the length of Line segment A B? Round to the nearest tenth.

19.3 in.
21.3 in.
23.5 in.
68.0 in.

Respuesta :

Answer:

21.3 feet

Step-by-step explanation:

In the right triangle Δ ABC, the ∠ C = 90° and ∠ A = 25°.

Now, length of BC = 9 inches and length of the hypotenuse i.e. AB is c that we have to calculate.

Now, using trigonometry we can say that

[tex]\sin 25^{\circ} = \frac{BC}{AB} = \frac{9}{c}[/tex]

[tex]c = \frac{9}{\sin 25^{\circ}} = 21.29[/tex] feet ≈ 21.3 feet. (Answer)

The required length of Line segment AB is 21.3inches.

Given that,

Triangle ABC is shown.

Angle ACB is 90 degrees and angle BAC is 25 degrees.

The length of BC is 9 inches and the length of hypotenuse BA is c.

We have to find,

What is the length of Line segment AB.

According to the question,

In the right triangle Δ ABC, the ∠ C = 90° and ∠ A = 25°.

Now, length of BC = 9 inches,

And length of the hypotenuse.

AB is c is going to calculate.

Therefore,

[tex]Sin\theta = \dfrac{perpendiculaar}{hyptotenuse} \\\\Sin25 = \dfrac{BC}{AB} \\\\Sin25 = \dfrac{9}{c}\\\\c = \dfrac{9}{sin25} \\\\c = \dfrac{9}{0.42}\\\\c = 21.29 \ inches\\\\c = 21.3 \ inches \ (approx)[/tex]

Hence, The required length of Line segment AB is 21.3inches.

To know more about Trigonometry click the link given below.

https://brainly.com/question/17006253

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