Answer:
M_o = 18.84 N*m in the clockwise direction.
Explanation:
Given:
- Force F = 120 N
- base b = 610 mm
- height h = 330 mm
Find:
Moment M_o about origin and its direction:
Solution:
- The force has two components F_x and F_y along base b and height h, respectively:
F_x = F*cos(Q)
F_x = F*(h / sqrt (h^2 + b^2))
F_x = 120*(330 / sqrt (330^2 + 610^2))
F_x = 57.098 N
- We can skip F_y as it passes through the the origin, hence moment produced is zero.
- Moment about O is :
M_o = F_x * h
M_o = 57.098*.33
M_o = 18.84 N*m in the clockwise direction.