Explanation:
It is known that 1 [tex]cm^{3}[/tex] is equal to 1 ml. And, volume of water in graduate cylinder ([tex]V_{w}[/tex]) is 37.0 ml.
Dimension of cube, a = 3.0 cm
Hence, volume of cube, [tex]V_{c}[/tex] = [tex]a^{3}[/tex] = [tex](3.0 cm)^{3}[/tex]
= 27 [tex]cm^{3}[/tex]
So, 27 [tex]cm^{3} \times \frac{1 ml}{1 cm^{3}}[/tex]
= 27 ml
Initially, it is given that volume of water in both the graduate cylinders is 37.0 ml. So, when cube is lower into the graduate cylinder then volume of water displaced by the cube will raise the height of water level in the graduate cylinder.