Suppose you have two 100 mL graduated cylinders. In each cylinder, there is 37.0 mL of water. You also have two cubes: one is lead, and the other is aluminum. The density of lead and aluminum are 11.3 g/mL and 2.70 g/mL respectively. Each cube measures 3.0 cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders? Express your answer to three significant figures and include the appropriate units.

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Explanation:

It is known that 1 [tex]cm^{3}[/tex] is equal to 1 ml. And, volume of water in graduate cylinder ([tex]V_{w}[/tex]) is 37.0 ml.

Dimension of cube, a = 3.0 cm

Hence, volume of cube, [tex]V_{c}[/tex] = [tex]a^{3}[/tex] = [tex](3.0 cm)^{3}[/tex]

                                          = 27 [tex]cm^{3}[/tex]

So,       27 [tex]cm^{3} \times \frac{1 ml}{1 cm^{3}}[/tex]

                          = 27 ml

Initially, it is given that volume of water in both the graduate cylinders is 37.0 ml. So, when cube is lower into the graduate cylinder then volume of water displaced by the cube will raise the height of water level in the graduate cylinder.

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