Allowed values for y: [tex]-2,-\frac{3}{2},-1,-\frac{1}{2},0[/tex]
Step-by-step explanation:
The domain of a function [tex]f(x)[/tex] represents the set of values for which the function is defined. In other words, it represents the values of x that are allowed.
The function in this problem is:
[tex]y=\frac{1}{4}x-1[/tex]
And the domain is
D: {-4,-2,0,2,4}
This means that these are the only allowed values for x. We can find the range of the functions (the possible values for y) simply by substituting these values of x into the function. We get:
For x = -4,
[tex]y=\frac{1}{4}(-4)-1=-1-1=-2[/tex]
For x = -2,
[tex]y=\frac{1}{4}(-2)-1=-\frac{1}{2}-1=-\frac{3}{2}[/tex]
For x = 0,
[tex]y=\frac{1}{4}(0)-1=-1[/tex]
For x = 2,
[tex]y=\frac{1}{4}(2)-1=\frac{1}{2}-1=-\frac{1}{2}[/tex]
For x = 4,
[tex]y=\frac{1}{4}(4)-1=1-1=0[/tex]
Therefore, the allowed values for y are:
[tex]-2,-\frac{3}{2},-1,-\frac{1}{2},0[/tex]
Learn more about domain and range:
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