Respuesta :

Allowed values for y: [tex]-2,-\frac{3}{2},-1,-\frac{1}{2},0[/tex]

Step-by-step explanation:

The domain of a function [tex]f(x)[/tex] represents the set of values for which the function is defined. In other words, it represents the values of x that are allowed.

The function in this problem is:

[tex]y=\frac{1}{4}x-1[/tex]

And the domain is

D: {-4,-2,0,2,4}

This means that these are the only allowed values for x. We can find the range of the functions (the possible values for y) simply by substituting these values of x into the function. We get:

For x = -4,

[tex]y=\frac{1}{4}(-4)-1=-1-1=-2[/tex]

For x = -2,

[tex]y=\frac{1}{4}(-2)-1=-\frac{1}{2}-1=-\frac{3}{2}[/tex]

For x = 0,

[tex]y=\frac{1}{4}(0)-1=-1[/tex]

For x = 2,

[tex]y=\frac{1}{4}(2)-1=\frac{1}{2}-1=-\frac{1}{2}[/tex]

For x = 4,

[tex]y=\frac{1}{4}(4)-1=1-1=0[/tex]

Therefore, the allowed values for y are:

[tex]-2,-\frac{3}{2},-1,-\frac{1}{2},0[/tex]

Learn more about domain and range:

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