Question

find the slope of the line that passes theough each pair of points.
8). (-4,5), (1,1)

9). (0,0), (-1,3)

10). (5,3), (-2,-4)​

Answer 1

Answer:

Step-by-step explanation:

Slope = change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

8) The line passes through (- 4,5) and (1,1),

y2 = 1

y1 = 5

x2 = 1

x1 = - 4

Slope = (1 - 5)/(1 - - 4) = - 4/5

9) The line passes through (0, 0) and (- 1, 3),

y2 = 3

y1 = 0

x2 = - 1

x1 = 0

Slope = (3 - 0)/(- 1 - 0) = 3/- 1

Slope = - 3

10)The line passes through (5, 3) and (- 2, -4),

y2 = - 4

y1 = 3

x2 = - 2

x1 = 5

Slope = (- 4 - 3)/(- 2 - 5) = - 7/- 7

Slope = 1

Answer 2

Answer : The slope of line for the  following pairs of points are:

Part 8 : $m=\frac{-4}{5}$

Part 9 : $m=-3$

Part 10 : $m=1$

Step-by-step explanation :

The general form for the formation of a linear equation is:

$(y-y_1)=m\times (x-x_1)$

where,

x and y are the coordinates of x-axis and y-axis respectively.

m is slope of line.

Now we have to calculate the slope of line for the  following pairs of points.

Formula used :

$m=\frac{(y_2-y_1)}{(x_2-x_1)}$

Part 8 :

$(x_1,y_1)=(-4,5)$ and $(x_2,y_2)=(1,1)$

$m=\frac{(1-5)}{(1-(-4))}$

$m=\frac{-4}{5}$

Part 9 :

$(x_1,y_1)=(0,0)$ and $(x_2,y_2)=(-1,3)$

$m=\frac{(3-0)}{(-1-0)}$

$m=\frac{3}{-1}$

$m=-3$

Part 10 :

$(x_1,y_1)=(5,3)$ and $(x_2,y_2)=(-2,-4)$

$m=\frac{(-4-3)}{(-2-5)}$

$m=\frac{-7}{-7}$

$m=1$