Respuesta :
Answer:
(C) [tex]3.6m^{5}[/tex]
Explanation:
[tex]r=km^2\\[/tex] = [tex]3m^2[/tex]
Since the object is a solid sphere, the equation for rotational inertia is:
[tex]I = \frac{2}{5}mr^2[/tex]
[tex]I=\frac{2}{5}m(3m^2)^2=\frac{2}{5}*9m^5=3.6m^5[/tex]
The correct option is (C) which is,
[tex]I=3.6m^5[/tex]
Given-
The equation for the radius according to the experiment,
[tex]r=km^{2}[/tex]
{here constant K=3}
By putting the value of k in the above equation we get,
[tex]r=3m^{2}[/tex]
It is known that for a spherically shaped object the moment of inertia can be written as,
[tex]I=\dfrac{2}{5} mr^{2}[/tex]
Put the value of radius in the above formula of Inertia we get,
[tex]I=\dfrac{2}{5} m[3m^2]^{2}[/tex]
[tex]I=\dfrac{2}{5} *9m^5[/tex]
[tex]I=3.6m^5[/tex]
Hence, the correct option is (C) which is,
[tex]I=3.6m^5[/tex]
For more about the moment of Inertia, follow the link below,
https://brainly.com/question/6953943?referrer=searchResults
