Question

At a distance of 0.186 cmcm from a large uniform sheet of charge, the electric field is 490 N/CN/C . What is the electric field 1.35 cmcm from the sheet?

Answer 1

Answer:

$E=490 N/C$

Explanation:

We are given that

At distance 0.186 cm

The electric field,E=490 N/C

We have to find the electric filed at distance 1.35 cm from the sheet.

We know that

Electric field due to large sheet ,E=$\frac{\sigma}{2\epsilon_0}$

Where $\sigma$=Surface charge density

$\epsilon_0=8.85\times 10^}{-12}C^2/Nm^2$

Electric filed of sheet does not depend on distance.It is  constant.

Electric filed at distance 0.186 cm=490 N/C

Therefore, the electric filed at distance 1.35 cm is also 490 N/C.

Hence, at distance 1.35 cm , the electric filed $E=490 N/C$