Question

A newly hypothetically discovered element, Ab, has 2 stable isotopes. 130Ab and 132Ab. The isotopic mass of 130Ab is 129.6785 and the isotopic mass of 132Ab is 131.3456. The atomic weight of Ab is 130.956 amu. What is the % abundance of 130Ab?

Answer 1

Answer: The percentage abundance of Ab-130 and Ab-132 isotopes are 23.40% and 76.60% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of Ab-130 isotope be x and that of Ab-132 isotope be (1-x)

• For isotope 1 (Ab-130) :

Mass of isotope 1 = 129.6785 amu

Fractional abundance of isotope 1 = x

• For isotope 2 (Ab-132) :

Mass of isotope 2 = 131.3456 amu

Fractional abundance of isotope 2 = (1 - x)

Putting values in equation 1, we get:

$130.956=[(129.6785\times x)+(131.3456\times (1-x))]\\\\x=0.234$

Percentage abundance of Ab-130 isotope = $0.234\times 100=23.40\%$

Percentage abundance of Ab-132 isotope = $(1-0.234)=0.766\times 100=76.60\%$

Hence, the percentage abundance of Ab-130 and Ab-132 isotopes are 23.40% and 76.60% respectively.

Answer 2

The study of chemicals and bonds is called chemistry.

The correct answer is The percentage abundance of Ab-130 and Ab-132 isotopes are 23.40% and 76.60% respectively.

The average atomic mass of an element is defined as the sum of masses of each isotope multiplied by their natural fractional abundance.

The formula used to calculate average atomic mass follows:

• $atomic\ mass * fractional \ abundance$

What are isotopes?

• The isotope is defined as the atom which has the same electrons but different neutrons.

For isotope 1 (Ab-130) :

• Mass of isotope 1 = 129.6785 amu

• Fractional abundance of isotope 1 = x

For isotope 2 (Ab-132) :

• Mass of isotope 2 = 131.3456 amu
• Fractional abundance of isotope 2 = (1 - x)

Putting values in equation 1, after solving we will get as follows;-

$130.956 =(129.6785*x)+131.3456*(1-x)$

after solving the value of x will be0.234.

Percentage abundance of Ab-130 isotope = 0.234*100 =23.4%

Percentage abundance of Ab-132 isotope = 0.766*100 =76.6%

Hence, the percentage abundance of Ab-130 and Ab-132 isotopes are 23.40% and 76.60% respectively.

For more information about isotopes, refer to the link:-

https://brainly.com/question/11588623