Question

Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell

Answer 1

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

Answer 2

The edge length of the unit cell will be "628 pm"

Given:

• Radius, R = 272 pm

or,

                        = $272\times 10^{-12}$

                        = $2.72\times 10^{-10} \ m$

As we know, the formula,

→ $a = \frac{4R}{\sqrt{3} }$

By substituting the values, we get

     $=\frac{(4)\times (2.72\times 10^{-10})}{\sqrt{3} }$

     $= 6.2815\times 10^{-10}$

     $= 628 \ pm$

Thus the answer above is right.  

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