Respuesta :
Answer:
[tex]\dfrac{5}{9}[/tex]
Step-by-step explanation:
Let's get the sample space first. What are the possibilities? Kevin could pick
2 nickels = 10 cents,
2 dimes = 20 cents,
2 quarters = 50 cents,
1 nickel + 1 dime = 15 cents,
1 nickel + 1 quarter = 30 cents,
1 quarter + 1 dime = 35 cents.
There are two ways of picking in each of the last three---by reversing the order of picking e.g. nickel then dime, and dime them nickel. In all, we have 9 possible outcomes.
Of these, 5 yield a sum that is at least 30:
quarter + quarter (50c), nickel + quarter (30c, twice) and quarter + dime (35c, twice)
The probability of having the sum of two coins equal to, at least, 30 is thus [tex]\dfrac{5}{9}[/tex].