Respuesta :

Option A is the relationship which shows a direct variation.

Step-by-step explanation:

The direct variation is a relationship between two variables in which one is the multiple of the other. It is given by the relation

[tex]\frac{y}{x}=k[/tex]

Option A:

For [tex]x=2[/tex] and [tex]y=1[/tex],

[tex]\frac{y}{x}=\frac{1}{2}[/tex]

For [tex]x=4[/tex] and [tex]y=2[/tex],

[tex]\frac{y}{x}=\frac{2}{4}= \frac{1}{2}[/tex]

Since, the constant k is equal for all the values of x and y in the table, this relationship is a direct variation.

Option B:

For [tex]x=2[/tex] and [tex]y=4[/tex],

[tex]\frac{y}{x}=\frac{4}{2}= 2[/tex]

For [tex]x=4[/tex] and [tex]y=16[/tex],

[tex]\frac{y}{x}=\frac{16}{4} =4[/tex]

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option C:

For [tex]x=1[/tex] and [tex]y=3[/tex]

[tex]\frac{y}{x} =\frac{3}{1} =3[/tex]

For [tex]x=2[/tex] and [tex]y=5[/tex]

[tex]\frac{y}{x} =\frac{5}{2}[/tex]

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option D:

For [tex]x=1[/tex] and [tex]y=-1[/tex]

[tex]\frac{y}{x} =\frac{-1}{1} =-1[/tex]

For [tex]x=2[/tex] and [tex]y=2[/tex]

[tex]\frac{y}{x} =\frac{2}{2} =1[/tex]

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Thus, Option A is the relationship which shows direct variation.

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