Answer:
One solution [tex]x=2[/tex]
Step-by-step explanation:
Given the equation
[tex]0.5(x+12)=4x-1[/tex]
First, multiply this equation by 10:
[tex]10\cdot 0.5(x+12)=10(4x-1)\\ \\5(x+12)=40x-10\\ \\5x+60=40x-10[/tex]
Separate terms with x and without x in different parts of the equation:
[tex]5x-40x=-10-60\\ \\-35x=-70\\ \\35x=70\\ \\x=\dfrac{70}{35}\\ \\x=2[/tex]