Answer:
The 24th term is 80 and the sum of 24 terms is 1092.
Explanation:
Given that,
The arithmetic series is
11,14,17,........24
First term a = 11
Difference d = 14-11=3
We need to calculate the 24th term of the arithmetic sequence
Using formula of number of terms
[tex]t_{n}=a+(n-1)d[/tex]
Put the value into the formula
[tex]t_{24}=11+(24-1)\times3[/tex]
[tex]t_{24}=80[/tex]
[tex]t_{24}=u_{24}=80[/tex]
We need to calculate the sum of the first 24 terms of the series
Using formula of sum,
[tex]S_{n}=\dfrac{n}{2}(a+u_{24})[/tex]
Put the value into the formula
[tex]S_{n}=\dfrac{24}{2}\times(11+80)[/tex]
[tex]S_{n}=1092[/tex]
Hence, The 24th term is 80 and the sum of 24 terms is 1092.