Answer:
See answer below
Step-by-step explanation:
This is a separable equation, so we solve it like this:
[tex]\frac{dy}{y}=9dx \implies (\ln(y))'=9dx \implies ln(y)=9x+c \implies y=e^{9x+c} \implies y=ke^{9x}[/tex]
Then [tex]y(x)=ke^{9x}[/tex] for any constant k (this is the general solution). This solution is defined in (-∞,∞) (there are no singularities) and when x tends to infinity, no terms of the solution vanish, hence there are no transient terms.