432 grams of N₂I₆
Explanation:
First we have to divide the given number of molecules (3.3\times10^2^8) by the Avogadro's number of molecules (6.022\times10^2^8), so that we will get the number of moles as 0.5.
Then the 0.5 moles of N₂I₆ is multiplied by the molar mass of N₂I₆ which is 789 g/mol, we will get the mass of N₂I₆ as 432 grams.
So the mass of the N₂I₆ obtained is 432 grams.
[tex]3.30 \times 10^2^3molecules / 1 \times 1 mol N_2I_6/6.022 \times10^2^3 molecules \times 789 g / mol/ 1 \ mol N_2I_6 = 432 g\of \ N_2I_6[/tex]
