Option c: [tex]\frac{1}{4 x}[/tex]
Step-by-step explanation:
The expression is [tex](4x^{3})(2x)^{-4}[/tex]
Applying the exponent rule, we have,
[tex]\frac{4x^{3} }{(2x)^{4} }[/tex]
Multiplying the denominator,
[tex]\frac{4x^{3} }{2^{4} x^{4} }[/tex]
Rewriting this expression,
[tex]\frac{4x^{3} }{16 x^{4} }[/tex]
Cancelling the common terms, we have,
[tex]\frac{1 }{4x }[/tex]
Thus, the expression equivalent to [tex](4x^{3})(2x)^{-4}[/tex] is [tex]\frac{1 }{4x }[/tex]