The inverse of the function is [tex]y=\pm \sqrt{\frac{x+8}{2}}[/tex]
Explanation:
To find the inverse of the equation [tex]y=2x^{2} -8[/tex], we need to interchange the variables x and y for the variables y and x.
Thus, the equation becomes
[tex]x=2y^{2} -8[/tex]
Now, we shall find the value of y.
Now, adding 8 to both sides of the equation, we have,
[tex]x+8=2y^{2}[/tex]
Interchanging the sides,
[tex]2y^{2} =x+8[/tex]
Dividing by 2 on both sides,
[tex]y^{2} =\frac{x+8}{2}[/tex]
Taking square root on both sides,
[tex]y=\pm \sqrt{\frac{x+8}{2}}[/tex]
Thus, the inverse of the function is [tex]y=\pm \sqrt{\frac{x+8}{2}}[/tex]