Respuesta :
Answer:
[tex]12y+x-12=0[/tex]
Step-by-step explanation:
If I'm not mistaken by the question, we have
[tex]x+4y=\dfrac{2}{3}x+4[/tex]
Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)
[tex]3\timesx+3\times4y=3\times\dfrac{2}{3}x+3\times4[/tex]
[tex]3x+12y=2x+12[/tex]
Putting all terms on the LHS (left hand side) and evaluating,
[tex]12y+x-12=0[/tex]
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