Question

Draw the Lewis structure (including all lone pair electrons and any formal charges) for one of the four possible isomers of C3H9N

Answer 1

Answer:

To draw the Lewis structure of one of the isomers of the C3H9N, propylamine is chosen, see attached drawing.

Explanation:

• First, the electronic configuration of each atom involved is elaborated, in our case it would be nitrogen, hydrogen and carbon. This in order to determine the valence electrons.

N (Z=7) $1S^{2} 2S^{2} 2p^{3}$ 5 electrons

H (Z=1) $1S^{1}$ 1 electron

C (Z=6)  $1S^{2} 2S^{2} 2p^{2}$ 4 electrons

• The necessary electrons are sought for compliance with the octet rule. The carbons with their 4 links complies with the octet rule.
• To locate the non-bonding electrons, a difference is made between the total valence electrons and the linkers. The nitrogen atom has 6 assigned electrons and a non-binding pair.
• Finally the Lewis structure is made.