Answer:
See explanation below
Explanation:
You are missing the rest of the question. Luckily I was able to find it, so, in picture 1, you have the whole question, and we will answer it by parts.
a) Type of glassware to use
In this case, it's very important to be accurate but also, we need to know the function in which you want to prepare this solution. In this case, We will assume that we want to prepare the solution and then, stock it in the lab. In these cases, it's always better to use the volumetric ball, because with this we can use a top in the glassware and the concentration will remain the same. You can use another glassware to make the measures of water to be more accurate but, to stock this solution, it's always better the volumetric ball.
b) Correct amount of solute to use:
In this case, the sucrose, is a solid compound, therefore, the best way to measure this is using a balance and weight the required mass basing on the concentration of the solution. So, it's best to measure out the grams of solute in a balance.
The amount needed is the following:
M = n/V
n = M*V
n = 0.150 * 0.250 = 0.0375 moles
to get the mass:
m = n*MM
The molar mass of sucrose is 342.3 g/mol so:
m = 0.0375 * 342.3
m = 12.84 g
c) How the solute and solvent be mixed
Finally for this part, now that you have weight the mass of sucrose needed, all you have to do is put the solute on the volumetric ball, and add some water. This way, the sucrose will mix with the water and become a solution. Then, you should complete the volume to 250 mL to get the solution at 0.150 M.
