Solving a right triangle (round to the nearest tenth)

Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the given angles from 180 for A
A = 180° - (90 + 46)° = 180° - 136° = 44°
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tan46° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{b}{23}[/tex]
Multiply both sides by 23
23 × tan46° = b, thus
b ≈ 23.8 ( to the nearest tenth )
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cos46° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{23}{c}[/tex]
Multiply both sides by c
c × cos46° = 23 ( divide both sides by cos46° )
c = [tex]\frac{23}{cos46}[/tex] ≈ 33.1 ( to the nearest tenth )