Find the magnitude of the electric field at a point 0.120 mm outside the surface of the sphere. Express your answer in newtons per coulomb.

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Answer:

So, if the sphere has net amount of charge on it, such that the test charge will experience its intensity in the given region of influence. As, the charge particles size plays a very important role in this regards, as the total distribution of the net charge occurs on the surface of the sphere.

So, we have the following formula in order to make the calculations and have the results, which is as follows:

  • E=F/q, (while "F" is the net amount of force applied by the charged body when the test charge,q is placed in its field)
  • And if we analyze the Gauss's law we have, Ф=q/∈,
  • While, we can obtain the required results by putting all the data into the following equation,as follows:
  • E=kq/r².

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