Answer:
[tex]\vec{F}= -3.52\times 10^{-13}\hat{i}\ N[/tex]
Explanation:
given,
charge = -5.0 μC
Electric force, F = 11 i^ N
force would a proton experience = ?
we know
[tex]\vec{F} = q \vec{E}[/tex]
[tex]11\hat{i} = -5 \times 10^{-6} \vec{E}[/tex]
[tex]\vec{E} =-2.2 \times 10^{6}\hat{i}[/tex]
we know charge of proton is equal to 1.6 x 10⁻¹⁹ C
using formula
[tex]\vec{F} = q \vec{E}[/tex]
[tex]\vec{F}= 1.6 \times 10^{-19}\times -2.2 \times 10^{6}\hat{i}[/tex]
[tex]\vec{F}= -3.52\times 10^{-13}\hat{i}\ N[/tex]
Force experienced by the photon in the same field is equal to [tex]\vec{F}= -3.52\times 10^{-13}\hat{i}\ N[/tex]