Answer
given,
initial speed of car, u = 70 Km/h
final speed of car, v = 120 Km/h
Acceleration of the car = 6000 Km/h²
time taken by the car
using equation of motion
v = u + a t
120 = 70 + 6000 x t
6000 t = 50
t = 8.33 x 10⁻³ hr
distance travel in this time
v² = u² + 2 a s
120² = 70² + 2 x 6000 x s
[tex]s = \dfrac{120^2-70^2}{2\times 6000}[/tex]
[tex]s = 0.792\ Km[/tex]
distance travel by the car is equal to 0.792 Km
