Answer:
1.09 L
Explanation:
There is some info missing. I think this is the original question.
Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.
The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:
100 g × (1 mol/255.43 g) = 0.391 mol
0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:
0.391 mol × (1 L/0.360 mol) = 1.09 L
Answer:
The volume of the solution is 1.09 L
Explanation:
Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.
Step 1: Data given
Molarity of the barium acetate = 0.360 M
Mass of barium acetate = 100 grams
Molar mass barium acetate = 255.43 g/mol
Step 2: Calculate moles of barium acetate
Moles = mass / molar mass
Moles = 100.0 grams / 255.43 g/mol
Moles = 0.3915 moles barium acetate
Step 3: Calculate volume of solution
Molarity = moles / volume
Volume = moles / molarity
Volume = 0.3915 moles / 0.360 M
Volume = 1.0875 L ≈ 1.09 L
The volume of the solution is 1.09 L
