Answer:
The magnetic field B of the transmission line is 4.5·10^(-6)T. The ratio B/Be is 0.0009% (there is no risk to human health)
Explanation:
we will consider a dc transmission line as an infinite longitudinal line in the Z-axis with a dc current of 180 A. To solve the problem we will use ampere's law. We can consider the geometry of the problem (Rotational symmetry in respect of Z-axis) than the field B is annular with center in the transmission line.
[tex]\vec{B}(r,\varphi,z)=B(r)\vec{\varphi}[/tex]
[tex]\displaystyle\oint_{C} \vec{B}(r)\,\vec{dl}=\mu I_c[/tex]
We will use a circular amperian curve C. Therefore:
[tex]\displaystyle\oint_{C} \vec{B}(r)\,\vec{dl}=\int_{0}^{2\pi} B(r)\vec{\varphi}\,\vec{\varphi}rd\varphi=B(r)r\int_{0}^{2\pi} \,d\varphi=B(r)r2\pi=\mu I_c[/tex]
[tex]B(r)=\displaystyle\frac{\mu 180A}{r2\pi}[/tex]
For a height of 8.0m (r=8m):
[tex]B(8m)=\displaystyle\frac{\mu 180A}{8m2\pi}=4.5\cdot10^{-6}T[/tex]
Compared to the earth magnetic field:
[tex]\displaystyle\frac{B}{B_e}\%= \frac{B}{B_e}100=0.0009\%[/tex]