Answer:
The deceleration is 0.18 m/s²
Explanation:
Hi there!
Using Newton´s second law, we can calculate the deceleration:
∑F = m · a
Where:
∑F = the sum of all forces in a given direction.
m = mass of the object.
a = acceleration.
Solving for a:
∑F/m = a
The only force acting on the meteor is the applied force of 8.6 N. So, the acceleration will be:
8.6 N / 48.9 kg = a
a = 0.18 m/s²
The deceleration is 0.18 m/s² or, in other words, the acceleration is -0.18 m/s²
Have a nice day!
