Respuesta :
Answer:
[NaNO₃] = 5.72 M
Explanation:
Molarity is a sort of concentration.
It says the moles of solute, that are contained in 1L of solution.
The volume is in mL, so let's convert to L.
250 mL . 1 L / 1000 mL = 0.250 L
Let's convert now, the mass of NaNO₃, our solute into moles
122 g / 85 g/mol = 1.43 moles
Molarity = mol / L → 1.43 mol / 0.250L = 5.72 M
The concentration of the sodium nitrate solution has been 5.72 mol/L.
The concentration has been defined as the proportion of the solute to the solvent. The concentration with presence of 1 mole of solute in a liter of solution has been given by molarity.
Concentration of Sodium Nitrate
The molarity of the solution has been given by:
[tex]\rm Molarity=\dfrac{Mass}{Molar\;mass}\;\times\;\dfrac{1000}{volume\;(mL)}[/tex]
The mass of sodium nitrate in the solution has been 122 g.
The molar mass of sample has been 85 g/mol
The volume of the solution has been 250 ml.
Substituting the values for Molarity of the solution as:
[tex]\rm Molarity=\dfrac{122}{85}\;\times\;\dfrac{1000}{250}\\Molarity=1.435\;\times\;4\;mol/L\\Molarity=5.72\;g/mol[/tex]
The concentration of the sodium nitrate solution has been 5.72 mol/L.
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