Question

A uniform rope of length L and negligible stiffness hangs from a solid fixture in the ceiling. The free lower end of the rope is struck sharply at time t=0. What is the time t it takes the resulting wave on the rope to travel to the ceiling, be reflected, and return to the lower end of the rope?

Answer 1

Answer:

The wave produced is a standing wave.

y' = [2ymax - kx] cos wt.

y max is maximum displacement, k is angular wave number, x is equal to the length L, w is angular frequency, t is time.

The time taken for the wave to travel to the ceiling and get reflected is given as:

t = 1/f = (2L)/nv. Where n =, 1,2,3, .... and v is wave speed, f is wave frequency.

Answer 2

In this exercise we have to use wave knowledge to calculate the length of a string, so we have to give it by:

$t = (2L)/nv$

The wave produced is a standing wave:

$y' = [2(ymax) - kx] cos( wt)$

Where do we have to:

• Y MAX is maximum displacement

• K is angular wave number

• L is the length

• W is angular frequency

• T is time.

The time taken for the wave to travel to the ceiling and get reflected is given as:

$t = 1/f \\= (2L)/nv$

Where n =, 1,2,3, .... and v is wave speed, f is wave frequency.

See more about waves at: brainly.com/question/3004869