Answer:
aluminum bar carrying a higher load than steel bar
Explanation:
Given data;
steel abr
diameter = 5 mm
stress = 500 MPa
aluminium bar
diameter = 10 mm
stress = 150 MPa
we know
stress = laod/area
for steel bar
[tex]500 = \frac{P}{\frac{\pi}{4} 5^2}[/tex]
solving for P
P = 9817.47 N
for Aluminium bar
[tex]150 = \frac{P}{\frac{\pi}{4} 10^2}[/tex]
solving for P
P = 11790 N
aluminum bar carrying a higher load than steel bar