Answer:
= 48.077 kcal
Explanation:
The balanced equation is :
[tex]Na_{2}O(s)+2HI(g)\rightarrow 2NaI(s)+H_{2}O(l)[/tex]
[tex]\Delta H=-120Kcal[/tex]
Since the stoichiometric coefficient of Na2O = 1 hence its heat is
-120 Kcal/mol rather -120 Kcal only.
This means when 1 mole of the Na2O is burned , then 120 kcal of energy is released .
Molar mass of Na2O = 2(mass of Na) + 1(mass of O)
= 2(22.98)+16
=61.97 gram/mol
Molar mass = mass of the substance in grams present in 1 mole of it.
In 1 mole of Na2O , 61.97 gram of it is present.
Hence
61.97 gram of Na2O = -120 Kcal of heat is released
1 gram of Na2O =
[tex]/frac{-120kcal/mol}{61.9gram/mol}[/tex]
So,
24.8 gram of Na2O will produce,
[tex]/frac{-120kcal/mol}{61.9gram/mol}/times 24.8[/tex]
= -48.077 kcal of heat
You can also proceed through mole concept:
Calculate number of moles in 24.8 gram Na2O
[tex]Moles=\frac{given\ mass}{Molar\ mass}[/tex]
Moles of Na2O = 24.08/61.9 = 0.4007 moles
So these many moles will produces:
0.4007 x 120
=-48.07
The energy released when 24.8 g Na₂O reacts is 48.077 kcal this can be calculated by using the mole-concept ratio.
Na2O(s) + 2HI(g) → 2Nal(s) + H2O(l)
Since the stoichiometric coefficient of Na₂O = 1
Reaction summary:
This means that when 1 mole of the Na₂O is burned, then 120 kcal of energy is released.
Molar mass of Na₂O = 61.97 gram/mol
In 1 mole of Na₂O, 61.97 grams of it is present.
Hence.
61.97 grams of Na₂O = -120 Kcal of heat is released
24.8 grams of Na₂O will produce -48.077 kcal of heat
You can also proceed through mole concept:
Calculate number of moles in 24.8 gram Na₂O:
Moles of Na2O = 24.08/61.9 = 0.4007 moles
So, these many moles will produce:
0.4007 * 120 =-48.07 moles
Find more information about Number of moles here:
brainly.com/question/14464650
