Question

If the electric field between the plates has a magnitude of 1.4×105 V/m , what is the potential difference between the plates?

Answer 1

Answer: V = Ed

V = 107.8 Volts

The distance between plate is missing, below is a possible complete question:

A Parallel-plate Capacitor Has Plates Separated By 0.77 Mm,If the electric field between the plates has a magnitude of 1.4×105 V/m , what is the potential difference between the plates?

Explanation:

Potential difference V = electric field E × distance d

V = Ed

E = 1.4 × 10^5 V/m

d = 0.77mm = 0.77 × 10^-3 m

V = 1.4 × 0.77 × 10^(5-3) Volt

V = 1.078 × 10^2 Volts

V = 107.8 Volts