Answer:
The average cost of each dinner at Dave's party is $5.79.
Step-by-step explanation:
Given:
Dave ordered dinner for a party of 10 people.
Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.
Now, to find the average cost of each dinner at Dave's party.
So, we get the total amount for the dinner:
Three people ordered the $4.75 chicken dinner.
[tex]4.75\times 3=14.25[/tex]
Two people ordered the $4.95 fish dinner.
[tex]4.95\times 2=9.90[/tex]
Five had the beef dinner at a cost of $6.75.
[tex]6.75\times 5=33.75[/tex]
Total amount of dinner = [tex]14.25+9.90+33.75=\$57.90.[/tex]
Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:
[tex]57.90\div 10[/tex]
[tex]=\$5.79.[/tex]
Therefore, the average cost of each dinner at Dave's party is $5.79.
