Answer:
The width of the red tile would be [tex]2.25[/tex] inches.
Step-by-step explanation:
Given blue tile has a length of [tex]4.25[/tex] inches, and a width of [tex]6.75[/tex]inches.
Also, length of similar tile is [tex]12.75[/tex] inches.
Let us assume [tex]x[/tex] as the width of red tile.
It is given in the question that both tiles are similar.
So, their area will be the same.
Area of blue tile would be [tex]4.25\times 6.75=28.6875\ inch^2[/tex]
Area of red tile would be [tex]12.75\times x[/tex]
The area of blue tile would be equal to area of red tile.
[tex]28.6875=12.75\times x[/tex]
[tex]\frac{28.6875}{12.75}=x\\\\x=2.25[/tex]
So, the width of the red tile would be [tex]2.25[/tex] inches.