contestada

If a photon has frequency = 2.00 x 1014s-1 and the speed of light = 3.00 x 108ms-1, then what is its wavelength?

Respuesta :

Answer:

The photon has a wavelength of [tex]1.5x10^{-6}m[/tex]

Explanation:

The speed of a wave can be defined as:

[tex]v = \nu \cdot \lambda[/tex] (1)

Where v is the speed, [tex]\nu[/tex] is the frequency and [tex]\lambda[/tex] is the wavelength.

Equation 1 can be expressed in the following way for the case of an electromagnetic wave:

[tex]c = \nu \cdot \lambda[/tex] (2)              

 

Where c is the speed of light.    

Therefore, [tex]\lamba[/tex][tex]\lambda[/tex] can be isolated from equation 2 to get the wavelength of the photon.

[tex]\lambda = \frac{c}{\nu}[/tex] (3)

[tex]\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}[/tex]

[tex]\lambda = 1.5x10^{-6}m[/tex]

Hence, the photon has a wavelength of [tex]1.5x10^{-6}m[/tex]        

Summary:  

Photons are the particles that constitutes light.

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