Question

Write a balanced equation for the combustion of one mole of magnesium.
Manipulate the equations below so that they add up to the equation above.
MgO(s) + 2 HCl (aq) → MgCl2(aq) + H2O(1)
Mg(s) + 2 HCI (aq) + MgCl2(aq) + H2(g)
H2(g) + 12 Oz (g) + H2O(1)

Answer 1

The balanced equation for the combustion of one mole of magnesium is:

2Mg(s) + O₂(g) → 2MgO(s)

Now, if we identify the given equations as eq 1, eq 2, and eq 3, we have to do the following:

1) Inverse eq 1 and multiply by 2:

2MgCl₂(aq) + 2H₂O(l) → 2MgO(s) + 4HCl(aq)

2)Multiply eq 2 by 2

2Mg(s) + 4HCl(aq) → 2MgCl₂(aq) + 2H₂(g)

3)  Multiply eq 3 by 2

2H₂(g) + O₂ → 2H₂O(l)

4) Add eq 1, eq 2, and eq 3

2MgCl₂(aq) + 2H₂O(l) → 2MgO(s) + 4HCl(aq)

2Mg(s) + 4HCl(aq) → 2MgCl₂(aq) + 2H₂(g)

2H₂(g) + O₂ → 2H₂O(l)                                           +

2Mg(s) + O₂(g) → 2MgO(s)

Have a nice day!

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