Question

A bicyclist in the Tour de France has a speed of 27.0 miles per hour (mi/h) on a flat section of the road. What is this speed in (a) kilometers per hour (km/h), and (b) meters per second (m/s)?

Answer 1

Answer:

(a) $43.45\frac{km}{h}$

(b) $12.08\frac{m}{s}$

Explanation:

(a) 1 mile is equal to 1.609344 kilometers. So, we have:

$27\frac{mi}{h}*\frac{1.609344 km}{1mi}=43.45\frac{km}{h}$

(b) 1 mile is equal to 1609.34 meters. 1 hour is equal to 3600 seconds. So, we have:

$27\frac{mi}{h}*\frac{1609.34m}{1mi}=4.35*10^{4}\frac{m}{h}\\4.35*10^{4}\frac{m}{h}*\frac{1h}{3600s}=12.08\frac{m}{s}$