Answer:
Yes
Explanation:
Any transparent surface in practical is neither a perfect absorber of electromagnetic waves neither a perfect reflector. Generally all the transparent surfaces reflect some amount of irradiation and the other parts are absorbed and transmitted.
That is given by as relation:
[tex]\alpha+\rho+\tau=1[/tex]
where:
[tex]\alpha=[/tex] absorptivity which is defined as the ratio of the absorbed radiation to the total irradiation
[tex]\rho=[/tex] reflectivity is defined as the ratio of reflected radiation to the total irradiation
[tex]\tau=[/tex] transmittivity is defined as the ratio of total transmitted radiation to the total irradiation
