[tex]-2\frac{1}{2} +1\frac{1}{3}=\frac{-1}{6}[/tex]
Solution:
Given expression is [tex]-2\frac{1}{2} +1\frac{1}{3}[/tex].
Let us first convert mixed fraction into improper fraction.
[tex]-2\frac{1}{2} +1\frac{1}{3}=\frac{(-2\times 2) +1}{2} +\frac{(1\times 3) + 1}{3}[/tex]
[tex]=\frac{-4 +1}{2} +\frac{3 + 1}{3}[/tex]
[tex]=\frac{-3}{2} +\frac{4}{3}[/tex]
Take LCM for the denominators (LCM of 2, 3 = 6) and make the same.
[tex]=\frac{-3\times3}{2\times3} +\frac{4\times2}{3\times2}[/tex]
[tex]=\frac{-9}{6} +\frac{8}{6}[/tex]
[tex]=\frac{-1}{6}[/tex]
[tex]-2\frac{1}{2} +1\frac{1}{3}=\frac{-1}{6}[/tex]
Hence the fraction form of [tex]-2\frac{1}{2} +1\frac{1}{3}[/tex] is [tex]\frac{-1}{6}[/tex].