Question

If p is a pressure, V a velocity, and a fluid density, what are the dimensions (in the MLT system) of (a) p/, (b) pV, and (c)p/pV2?

Answer 1

Answer:p=ML^-1T^-2

b)PV=MT^-3

c)P/PV^2=T^2L^-2

Explanation:In dimensions,Mass in kg is represented by M

Length is represented by L in meters.

T represent Time in seconds,s.

Pressure=hpg,h=height or depth In m,a=density=kg/m^3

g=acceleration due to gravity,m/s^2

P=hag=mxkg/m^3 xm/s^2=m^2×kg/m^2×s^2=kgm^-1 s^-2=ML^-1T^-2

B)PV=pressure xvelocity

=ML^-1T^-2×distance/time

ML^-1T^-2×L/T=MT^-3

C)p/pv^2=1/V^2=(time/distance)^2=(T/L)^2=T^2L^-2