Answer:
The speed of the proton relative to the laboratory frame is 0.981c
Explanation:
Given that,
Speed of electron v= 0.90c
Speed of proton u= 0.70c
We need to calculate the speed of the proton relative to the laboratory frame
Using formula of speed
[tex]u'=\dfrac{u+v}{1+\dfrac{uv}{c^2}}[/tex]
Where, u = speed of the proton relative to the electron
v = speed of electron relative to the laboratory frame
Put the value into the formula
[tex]u'=\dfrac{0.70+0.90}{1+\dfrac{0.70\times0.90\times c^2}{c^2}}[/tex]
[tex]u'=c\dfrac{0.70+0.90}{1+(0.70\times0.90)}[/tex]
[tex]u'=0.981c[/tex]
Hence, The speed of the proton relative to the laboratory frame is 0.981c