Question

What is the x-intercept of y = 3x² + 6x + 3 ?
o
1
-1
3

Answer 1

Answer:

Therefore the  x-intercept of

$y=3x^{2}+6x+3$

is

$x=-1$

Step-by-step explanation:

Intercepts:

The line which intersect on x-axis and y-axis are called intercepts.

There are two intercepts:

y-intercept: The line which intersect at y-axis. So when the line intersect at y-axis X coordinate is zero.

x-intercept: The line which intersect at x-axis. So when the line intersect at x-axis Y coordinate is zero.

For  x-intercept of y = 3x² + 6x + 3

put y = 0

$0=3x^{2}+6x+3$

Dividing throughout by 3 we get

$0=x^{2}+2x+1$

$0=x^{2}+2\times 1\times x+1^{2}$

Which is nothing but in the identity form of (A+B)² = A² +2AB +B²

A = x

B = 1

Therefore Equation becomes

$(x+1)^{2}=0\\x+1=0\\x=-1$

Therefore the  x-intercept of

$y=3x^{2}+6x+3$

is

$x=-1$