Weekly wages at a certain factory are
normally distributed with a mean of
$400 and a standard deviation of $50.
Find the probability that a worker
selected at random makes between
$300 and $350.

Respuesta :

Answer: 0.1359

Step-by-step explanation:

mean = $400

Standard deviation = $50

Since the wages is normally distributed , the first thing is to find the z - score.

z = [tex]\frac{x-mean}{standard deviation}[/tex]

finding the z - value for 300 and 350 , we have

z = [tex]\frac{300-400}{50}[/tex]

z = [tex]\frac{-100}{50}[/tex]

2 = -2

also

z = [tex]\frac{350-400}{50}[/tex]

z = [tex]\frac{-50}{50}[/tex]

z = -1

The next thing is to check the calculated value on z - table.

From z - table :

P (z[tex]\leq[/tex] -2 ) = 0.0228

P ( z [tex]\leq -1[/tex] ) = 0.1587

combining the two

P ( -2[tex]\leq[/tex]z[tex]\leq[/tex]-1 ) = 0.1587 - 0.0228

P ( -2[tex]\leq[/tex]z[tex]\leq[/tex]-1 ) = 0.1359

Therefore , the the probability that a worker

selected at random makes between

$300 and $350 = 0.1359

Answer:13.5

Step-by-step explanation:

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