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28-01-2020
Physics

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A test charge of 0.002 C experiences a force of 0.50 N on it is placed in an electric field. Find the intensity of the electric field

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alankabisov0225 alankabisov0225

28-01-2020

Answer:

250 N/C

Explanation:

E=F/q=0,5N/0,002C=250N/C

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