Answer:
See explanation below for answer
Explanation:
We'll do this question in two parts:
a) Weight percent of the alloy:
This is pretty easy, all we have to do is to sum the mass of each element in the alloy and then, divide each mass between the total to get the percentage in weight. In other words:
%W = m/mtotal * 100
The total mass:
mtotal = 98 + 65 = 163 g
%Sn = 98/163 * 100 = 60.12%
%Pb = 65/163 * 100 = 39.88%
b) atom percent of the alloy:
In this case, we do something similar that in part a) with the difference that instead of using mass, we will use moles of each element. The molar mass of Tin and Lead reported are 118.71 g/mol and 207.2 g/mol. The expression to use will be:
C = n/ntotal * 100
so for each element, the moles are:
moles Sn = 98/118.71 = 0.8255 moles
moles Pb = 65/207.2 = 0.3137 moles
the total moles:
ntotal = 0.8255 + 0.3137 = 1.1392 moles
So the composition in atoms for each element is:
C Sn = 0.8255/1.1392 * 100 = 72.46%
C Pb = 0.3137/1.1392 * 100 = 27.54%
