Question

How much heat (in J) must be added to raise the temperature of 2.70 mol of air from 22.0°C to 32.0°C at constant volume? Assume air is completely diatomic.

Answer 1

Answer:

Heat required to raise the temperature will be 563.625 J

Explanation:

We have given number of moles n = 2.70 mole

Temperature is raises from 22°C to 32°C

So increase in temperature $\Delta T=32-22=10^{\circ}C$

It is given that air is diatomic so $c_v=\frac{5}{2}R=2.5\times 8.314=20.875$

We know that heat is given by $Q=nc_v\Delta T$

So heat will be equal to $Q=2.70\times 20.875\times 10=563.625J$

So heat required to raise the temperature will be 563.625 J