Answer:
The moment of inertia about the rotation axis is 117.45 kg-m²
Explanation:
Given that,
Mass of one child = 16 kg
Mass of second child = 24 kg
Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.
We need to calculate the moment of inertia
Using formula of moment of inertia
[tex]I=I_{1}+I_{2}[/tex]
[tex]I=(m+m_{1})\times r^2+(m+m_{2})\times r^2[/tex]
m = mass of seat
m₁ =mass of one child
m₂ = mass of second child
r = radius of rod
Put the value into the formula
[tex]I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2[/tex]
[tex]I=117.45\ kg-m^2[/tex]
Hence, The moment of inertia about the rotation axis is 117.45 kg-m²